If 9^(3-x) = 81^(4-2x) , then what would be the value of x?

Question

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be

Answer 1

9^(3-x) = 81^(4-2x)
=> 9^(3-x) = 9^(8-4x)
=> 3-x = 8-4x
=> 3x = 5
=> x=5/3

Answer 2

5/3 is the answer

Answer 3

9 ^( 3-x) =81^( 4-2x)
(3^2)^(3-x)=(3^4)^(4-2x)
3^(2*(3-x))=3^( 4*(4-2x))
on camparing
2(3-x) =4(4-2x)
6-2x=16-8x
-2x+8x=16-6
6x=10
x=10/6
x=5/3