0 0 0 = 6 1 1 1 = 6 2 2 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6
In the space you can use any kind of functions like addition subtraction division etc but you cannot bring up new numbers (eg: 2+2+2=6)
(0!+0!+0!)! = 6 (1+1+1)! = 6 2+2+2 = 6 (3*3)-3 = 6 sqrt(4)+sqrt(4)+sqrt(4) = 6 5+(5/5) = 6 6+6-6 = 6 7-(7/7) = 6 cuberoot(8)+cuberoot(8)+cuberoot(8) = 6 (sqrt(9)!)+9-9 = 6
1) 6 , 5 , 43.2 2) 5 , 4 , 31.25 3) 4 , 3 , 21.33 4) 3 , 2 , ?
Given positive real numbers x, y, and z that satisfy the following system of equations: x² + xy + y² = 9, y² + yz + z² = 4, z² + zx + x² = 1,
Find x + y + z
