What will be sum of x and y if x,y are part of series 4, 16, 7, 49, 13, 169, x, y

Question

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be

Answer 1

4, 16, 7, 49, 13, 169, x, y
4^2=16;;;;;;;1+6=7^2=49;;;;;;;;;4+9=13^2=169;;;;;;;1+6+9=16^2=256;;;;;x=16,,,y=256,,,x+y=272

Answer 2

4,16,7,49,13,169,16,256
X=16 and y=256
X+y=272

Answer 3

650
x=25
y=625
4, 7, 13, 25
3, 6, 12...

42, 72, 132, 252...

Comments

Good logic :)

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Thank you! I appreciate that.

Answer 4

13+9 , (13+9)^2