A four digit number , having all digits different and non odd , has sum of all digits equal to 12. The sum of middle two digits is equal to the first digit. Second digit is greater than third digit. What will be the product of first three digits ?
Since all digits are EVEN and Different
the number will be ::: 6420
product of first three digits ====48
I am a three digit number. The product of the first and last digits is less than 49. The sum of the first two digits is less than 16. The difference of the first and last digits is greater than 0. The sum of the digits is greater than 6. The difference of the last two digits is equal to 2. The sum of the last two digits is equal to 6. The sum of the first and last digits is equal to 8.
Using the digits 1 up to 9, two numbers must be made. The product of these two numbers should be as large as possible. All digits must be used exactly once. Which are the requested two numbers?
All the digits of the given number are different.
