Salil and Aarav can do a piece of work in 45 and 40 days respectively. They began the work together but Salil leaves after some days and Aarav finished the remaining work in 23 days. After how many days did Salil leave?
Salil's speed = (1 work/45 days) Aarav's speed = (1 work/40 days) Speed*Time= Work ((1/45)+(1/40))*x + (1/40)*23 = 1 X=9 Therefore after 9 days salil leaves.
One day work of Salil and Aarav are 1/45 and 1/40 respectively. One day work of both together=1/45 + 1/40 =(8+9)/360 =17/360 Let Salil and Aarav work together for x days Work completed by both in x days=17 X/360 Remaining work=1-17X/360 =(360-17X)/360 This remaining work was completed by Aarav in 23 days. and one day work of Aarav is 1/40 Work done by Aarav in 23 days=23/40=(360-17X)/360 9*23=360-17X 17X=360-207 17X=153 X=153/17 =9 Days
Rahul and Maneesh working separately can do a piece of work in 9 days and 12 days respectively. If they work for a day alternately, Rahul beginning, in how many days, the work will be completed?
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
B alone can complete the work in 45 days. A is 35% more efficient than B. If A and B together started the work but after 18 days A and B left. Then C alone completed the remaining work in 3 days. If they get Rs. 9750 as wages for the whole work, then what is the share of C in wages for the remaining work?
