With 3 boys and 4 girls, arrange any 1 boy at center & any 2 girls at corners. In how many methods this can be arranged.

Question

There are 3 boys and 4 girls. We have to arrange any 1 boy at the center and any 2 girls at corners. In how many methods these persons can be arranged.

Answer 1

For one boy at centre we have === 3 ways

For two girls at corner we have === 4ways for one end and 3 ways for other end === 12 ways

For remaining 2boys and 2 girls can be arranged in == 4! ways === 24 ways

Hence the possible arrangements are === 3*12*24 === 864 ways

Answer 2

select 2 girls from 4 and arrange them by 2! ways=12
and select 1 boy from 3 boys in 3c1 ways=3
now remaining 2 boys and 2 girls can be arranged in 4! ways =24
12x3x24=864 ways